Integration 积分
∫\int∫ is kind of like SSS in sumsumsum.
∫14x\int_1^4 x∫14x is different than ∑n=14n\sum_{n=1}^{4} n∑n=14n.
In ∑n=14n\sum_{n=1}^{4} n∑n=14n, n can only be increased by 1. So it will be 1+2+3+41 + 2 + 3 + 41+2+3+4.
But in ∫14x\int_1^4 x∫14x, xxx can be any number in interval [1,4][1, 4][1,4], dxdxdx is another conception that not related in this xxx. So it will be 1+...+2+...+3+...+41 + ... + 2 + ... + 3 + ... + 41+...+2+...+3+...+4
Last updated 6 years ago