(7, 4)循环码的生多项式 g(x)=x3+x2+1g(x)=x^3+x^2+1g(x)=x3+x2+1 , 则D(1010)的系循环码是多少?
(7, 4)
D(1010)
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n=2r−1n = 2^r - 1n=2r−1
n represents the length of codes
n
r represents the 监督码(不传递信息,只为纠错而加的东西)
r
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