(7, 4)
循环码的生多项式 g(x)=x3+x2+1 , 则D(1010)
的系循环码是多少?
1.
1010⇒d(x)=x3+x1 2.
==x7−4⋅d(x)x3⋅(x3+x)x6+x4 3.
rem[(x6+x4),g(x)]=1rem( a , b ) returns the remainder after division of a by b 4.
c(x)10=x6+x4+1⇓10001 hamming code
n=2r−1
n
represents the length of codes
r
represents the 监督码(不传递信息,只为纠错而加的东西)