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Electrical Engineering
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AC
Resistor
i
=
2
I
sin
(
w
t
+
ψ
i
)
u
=
R
i
=
2
R
I
sin
(
w
t
+
ψ
i
)
u
=
2
U
sin
(
w
t
+
ψ
i
)
\begin{align*} i &= \sqrt{2} I \sin(wt + \psi_i) \\ \\ \\ u = R i &= \sqrt{2} RI \sin(wt + \psi_i) \\ \\ u &= \sqrt{2} U \sin(wt + \psi_i) \end{align*}
i
u
=
R
i
u
=
2
I
sin
(
wt
+
ψ
i
)
=
2
R
I
sin
(
wt
+
ψ
i
)
=
2
U
sin
(
wt
+
ψ
i
)
As you can see, here not much to say.
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Last updated
6 years ago